반응형
226. Invert Binary Tree
Easy
Given the root
of a binary tree, invert the tree, and return its root.
Example 1:
Input: root = [4,2,7,1,3,6,9]
Output: [4,7,2,9,6,3,1]
Example 2:
Input: root = [2,1,3]
Output: [2,3,1]
Example 3:
Input: root = []
Output: []
Constraints:
- The number of nodes in the tree is in the range
[0, 100]
. -100 <= Node.val <= 100
나의 코드
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
class Solution:
def invertTree(self, root: Optional[TreeNode]) -> Optional[TreeNode]:
if not root:
return None
root.left, root.right = root.right, root.left
self.invertTree(root.left)
self.invertTree(root.right)
return root
728x90
반응형
'알고리즘 > LeetCode_Grind75' 카테고리의 다른 글
Grind75 - 21. Merge Two Sorted Lists 파이썬 (0) | 2024.11.28 |
---|---|
Grind75 - 121. Best Time to Buy and Sell Stock 파이썬 (0) | 2024.11.19 |
Grind75 - 704. Binary Search 파이썬 (0) | 2024.11.18 |
Grind75 - 242. Valid Anagram 파이썬 (0) | 2024.11.13 |
Grind75 - 125. Valid Palindrome 파이썬 (3) | 2024.11.04 |